bentuk sederhana akar 32 - 3akar2 + akar98
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[tex] \sqrt{32} - 3 \sqrt{2} + \sqrt{98} \\ \\ = \sqrt{16 \times 2} - 3 \sqrt{2} + \sqrt{49 \times 2} \\ \\ = \sqrt{ {4}^{2} \times 2 } - 3 \sqrt{2} + \sqrt{ {7}^{2} \times 2} \\ \\ = 4 \sqrt{2} - 3 \sqrt{2} + 7 \sqrt{2} \\ \\ = 1 \sqrt{2} + 7 \sqrt{2} \\ \\ = 8 \sqrt{2} [/tex]
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#BelajarMandiri BersamaBrainly
√32 - 3√2 + √98
= √16×2 - 3√2 + √49×2
= 4√2 - 3√2 + 7√2
= 8√2
[answer.2.content]
